A Paste by baldurk

1

// I dare you to do this solely in std::string :P         char init[256], test[256], incr[256];         char lne[256];         strcpy(lne, Line.c_str());                  char *c = strchr(lne, '(', ');         if(!c)         {             if(error)                 Print("syntax error on line '%s'\n", Line.c_str());             return byteLine;         }         c++;         while(*c == ' ', ') c++;         strcpy(init, c);         char *d = strchr(init, ';', ');         if(!d)         {             if(error)                 Print("syntax error on line '%s'\n", Line.c_str());             return byteLine;         }         *d = 0;         while(init[strlen(init)-1] == ' ', ') init[strlen(init)-1] = 0;         c = strchr(lne, ';', ')+1;         while(*c == ' ', ') c++;         strcpy(test, c);         strcpy(incr, strchr(c, ';', ')+1);         while(incr[0] == ' ' || incr[0] == '\t', ')         {             for(int q=0; q < (signed)strlen(incr); q++)                 incr[q] = incr[q+1];         }         d = strchr(test, ';', ');         if(!d)         {             if(error)                 Print("syntax error on line '%s'\n", Line.c_str());             return byteLine;         }         *d = 0;         d = strchr(incr, ', ')', ');         if(!d)         {             if(error)                 Print("syntax error on line '%s'\n", Line.c_str());             return byteLine;         }         *d = 0;         while(incr[strlen(incr)-1] == ' ', ') incr[strlen(incr)-1] = 0;         while(test[strlen(test)-1] == ' ', ') test[strlen(test)-1] = 0;         byteLine.op = FOR;         byteLine.par1 = init;         byteLine.par2 = test;         byteLine.par3 = incr;         return byteLine;